Tìm lim (căn bậc hai (4n^2 + 1) - căn bậc hai (n + 2)) / (2m - 3)
Câu hỏi:
Tìm lim\(\frac{{\sqrt {4{n^2} + 1} - \sqrt {n + 2} }}{{2n - 3}}\).
Trả lời:
lim\(\frac{{\sqrt {4{n^2} + 1} - \sqrt {n + 2} }}{{2n - 3}}\)
= lim\(\frac{{\sqrt {4 + \frac{1}{{{n^2}}}} - \sqrt {\frac{1}{n} + \frac{2}{{{n^2}}}} }}{{2 - \frac{3}{n}}} = \frac{{\sqrt 4 }}{2} = \frac{2}{2} = 1\).