Tìm x biết: a) x^3 -1/4 x =0 ; b) (2x – 1)^2 – (x + 3)^2 = 0; c) x^2(x – 3) + 12 – 4x = 0.
Câu hỏi:
Tìm x biết:
a) ;
b) (2x – 1)2 – (x + 3)2 = 0;
c) x2(x – 3) + 12 – 4x = 0.
Trả lời:
b) (2x – 1)2 – (x + 3)2 = 0
⇔ (2x – 1 – x – 3)(2x – 1 + x + 3) = 0
⇔ (x – 4)(3x + 2) = 0
Vậy .
c) x2(x – 3) + 12 – 4x = 0
⇔ x2(x – 3) – 4(x – 3) = 0
⇔ (x – 3)(x2 – 4) = 0
⇔ (x – 3)(x – 2)(x + 2) = 0
Vậy x ∈ {3; 2; –2}.