Cho 3 sin^4 x - cos^4 x = 1/2. Tính A = 2sin^4x - cos^4x
Câu hỏi:
Cho 3sin4x – cos4x = 12. Tính A = 2sin4x – cos4x.
Trả lời:
Ta có: sin2x + cos2x = 1
⇔ cos2x = 1 – sin2x
Mà 3sin4x – cos4x = 12.
⇔ 3sin4x – (1 – sin2x)2 = 12.
⇔ 3sin4x – 1 + 2sin2x – sin4x – 12= 0
⇔ 2sin4x + 2sin2x – 32 = 0
⇔ [sin2x=12sin2x=−32(L)
⇔ sin2x = 12
⇔ cos2x = 12
A = 2sin4x – cos4x = 2.(12)2−(12)2=14.